Arrange the three isomers of alkenes with molecular formula C5H10 in increasing
Order of their boiling points and write their IUPAC names?
Answers
Answer:
three isomers possible are cis-2-pentene,trans-2-pentene and 1-pentene. out of these three cis-2-pentene has more boiling point then trans isomer and 1-pentene has least boiling point.
Explanation:
The reason of this is that: Generally more the alkene is substituted more it is stable and hence has higher boiling point so 1-pentene is least substituted has lowest boiling point.
Both cis and trans-2-pentene are disubstituted but cis pentene has higher boiling point then trans isomer beacuse boiling point also depends upon intermolecular forces, the two alkyl groups on same side in cis isomer develop van der waal forces and also have a net dipole moment and this does not happen in case of trans isomer so cis 2 pentene has more boiling point then trans.
