Arrange these following atoms in order of decreasing first Ionization Energy
[Ne]3s2 3p5
, [Ar]4s2 3d10 4p3
, [Ar] 4s2 3d10 4
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Ionisation energy
Explanation:
- Generally, it is the minimum amount of energy that one must need to remove the electron which is most loosely bound in an isolated neutral gaseous atom or molecule.
- Using the above definition, we can arrange the given atoms into their decreasing first ionization energy.
- [Ne]3s2 3p5
- [Ar]4s2 3d10 4p3
- [Ar*] 4s2 3d10 4p2
[Ne] will have maximum ionisation energy due to half-filled orbital, and [Ar] will have more ionisation energy due to more exchange numbers in p orbitals that correspond to more exchange energy.
Thus, the order will be
[Ne] ≥ [Ar] ≥ [Ar*]
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