Question

Arrange these solids in their increasing order of intermolecular attractions: ice , I2, solid ammonia

Answer 1

Ice > Solid ammonia > $I_{2}$

Ice has strong hydrogen-bonding, using oxygen.

Solid ammonia has weaker hydrogen-bonding, using nitrogen.

Iodine has no hydrogen bonding. In its solid form, it only has London forces as forces of attraction.

Answer 2

Answer:

ice>Ammonia>Iodine ( I2 )