Question

Arranging the word in sequence based on last letter in c program.?



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Answer 1

{

 

char name[10][8], tname[10][8], temp[8];

int i, j, n;

 

printf("Enter the value of n \n");

scanf("%d", &n);

printf("Enter %d names n", \n);

 

for (i = 0; i < n; i++)

{

scanf("%s", name[i]);

strcpy(tname[i], name[i]);

}

 

for (i = 0; i < n - 1 ; i++)

{

for (j = i + 1; j < n; j++)

{

if (strcmp(name[i], name[j]) > 0)

{

strcpy(temp, name[i]);

strcpy(name[i], name[j]);

strcpy(name[j], temp);

}

}

}

 

printf("\n----------------------------------------\n");

printf("Input NamestSorted names\n");

printf("------------------------------------------\n");

 

for (i = 0; i < n; i++)

{

printf("%s\t\t%s\n", tname[i], name[i]);

}

 

printf("------------------------------------------\n");

 

}

Answer 2

#include<stdio.h>

#include<string.h>

int main()

{

char a[10],alpha;

int b;

printf("Enter a word: ");

scanf("%s",a);

b = strlen(a);

for(int i = 0; i < b; i++)

for(int j = 0; j < b; j++)

if(a[j] < a[i])

{

alpha = a[i];

a[i] = a[j];

a[j] = alpha;

}

printf("The reversed word is: %s", a);

return 0;

}

Output:

Enter a word : Sudhajoy

The reversed word is : yusojhda.

Hope it helps!