array of light falling normally on the face ab of an equilateral glass prism having the refractive index 3 by 2 placed in a water of index 4 by 3 will this race of 40 IR total internal reflection on striking the phase AC justify your answer
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However I was too searching for the answer
But as i too appeared the boards yesterday
My answer was as follows
Since, u = 1 / sin c {where u is the refractive index (u2/u1) and c is critical angle}
u2/u1 = 1 / sin c
3/2//4/3 = 1 / sin c
9/8 = 1 / sin c
Sin c = 8/9
c = approx 62.73° (calculated through calculator now)
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..
..
..
Now observe the figure
Since incident ray is perpendicular
Therefore it won't show any refraction or any reflection
While incident ray reaches AC
It would make a triangle with angle of prism 60° and perpendicular angle now angle of incident ray with ac is 180 - 60 + 90 = 30°
Angle of incidence = 90 - 30
= 60°
Since angle of incidence is less than critical angle, Ray will NOT suffer TIR
.
.
.
*This was my answer as ameture student*
*Kindly don't mark this as correct answer*
*I am too searching for this question's solution*
But as i too appeared the boards yesterday
My answer was as follows
Since, u = 1 / sin c {where u is the refractive index (u2/u1) and c is critical angle}
u2/u1 = 1 / sin c
3/2//4/3 = 1 / sin c
9/8 = 1 / sin c
Sin c = 8/9
c = approx 62.73° (calculated through calculator now)
..
..
..
..
Now observe the figure
Since incident ray is perpendicular
Therefore it won't show any refraction or any reflection
While incident ray reaches AC
It would make a triangle with angle of prism 60° and perpendicular angle now angle of incident ray with ac is 180 - 60 + 90 = 30°
Angle of incidence = 90 - 30
= 60°
Since angle of incidence is less than critical angle, Ray will NOT suffer TIR
.
.
.
*This was my answer as ameture student*
*Kindly don't mark this as correct answer*
*I am too searching for this question's solution*
atiya2:
it's easy try it
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