Question

Arron heats liquid in a beaker for 10 minutes. He takes the temperature every minute. What precautions is Arron taking?

Answer 1

Answer:

L=550cal/g

Explanation:

hope it helps you

Answer 2

Explanation:

550 cal/g

Assuming heater is supplying heat at uniform rate of Q˙cal/s

in 10 minutes total heat transferred =600×Q˙

This amount should be equal to heat gained by water =mcΔT where m is mass of water and c is specific heat capacity of water.

mcΔT=600Q˙

m×1calg−1C∘−1×(100−0)=600Q˙⇒Q˙=6m...(i)

The heater supplies heat at constant temperature to convert water into steam, the amount of heat is given by 

55minutes×60×sec×Q˙..(i) 

this amount should be equal to heat gained by water to convert into steam at constant temperature =mL where L is latent heat of vaporization 

3300Q˙=mL...(ii)

substituting value of Q˙ from equation (i)

 33006m=mL

L=550cal/g