Question

ars.
11. The number of members of a club is 625. If the number increases at the rate of
20%. every year, what will be the total numbers of members of the club after 3
years.
​

Answer 1

Question : 11. The number of members of a club is 625. If the number increases at the rate of 20% every year, what will be the total number of members of the club after 3 years.

Solution :

Principal (P) = 625

Rate (R) = 20% per year.

Time (T) = 3 years

$Amount (A) = P( { 1 + \frac{R}{100} })^{T} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= {625(1 + \frac{20}{100} })^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 625( \frac{100 + 20}{100}) ^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 625 \times \frac{120}{100} \times \frac{120}{100} \times \frac{120}{100 \:} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6 \times 6 \times 6 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1080$

Total number of members of the club after 3 years = 1080

Answer 2

Answer:

answer is 1080

Step-by-step explanation:

member of club=625

every year increase at the rate=20%

after 1 year=6/5

principal (p)

time (t)

rate (r)

p(1+r/100)³

625(1+20/100)³

625(100+20/100)³

625×120/200×120/100×120/100

divide by 6or5

6×6×6×5

216×5

1080

hands the answer is 1080