Question

Arshu was given 1 1/2 hours to do a test. He finished the test in 1 1/6 hours, How much earlier did he
finish his test?
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Answer 1

Given

• Time Given for the test ⇒$1\frac{1}{2}$ hours
• Time in which Arshu completed the test ⇒ $1\frac{1}{6}$ hours

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To Find

• How much earlier did Arshu complete the test.

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Solution

First we will convert the mixed fractions in the given data to improper fraction.

Time Given for the test ⇒$1\frac{1}{2}$ hours

⇒ $1\dfrac{1}{2} = \dfrac{1\times 2 +1}{2}$

⇒ $1\dfrac{1}{2} = \dfrac{2 +1}{2}$

⇒ $1\dfrac{1}{2} = \dfrac{3}{2}$

Time in which Arshu completed the test ⇒ $1\frac{1}{6}$ hours

⇒ $1\dfrac{1}{6} = \dfrac{1\times6 +1}{6}$

⇒ $1\dfrac{1}{6} = \dfrac{6 +1}{6}$

⇒ $1\dfrac{1}{6} = \dfrac{7}{6}$

Now we have to subtract $\frac{7}{6}$ from $\frac{3}{2}$

⇒ $\dfrac{3}{2}-\dfrac{7}{6}$

⇒ $\dfrac{3\times 3 }{2\times 3}-\dfrac{7\times 1 }{6\times 1}$

⇒ $\dfrac{9 }{6}-\dfrac{7}{6}$

⇒ $\dfrac{2}{6}$

⇒ $\dfrac{1}{3}$

∴ Arshu completed the test $\bf \frac{1}{3}$ hour before the given time.

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Answer 2

Step-by-step explanation:

Nehe solved 2/u part of an exercise while Neeru solved 4/5 of it. Who solved lesser part ?