Question

arthicmatic mean of 3 numbers is 40 all three numbers are different natural numbers is Louis is 19 what could be highest possible numbers of remaining two numbers​

Answer 1

Arithmetic mean = 40

Sum of the numbers = 3*40 = 120

Lowest is 19.

Sum of remaining two numbers = 120 - 19 = 101

101/2 = 50.5

So the highest possible values of remaining two numbers = 50 and 51