arthimetic mean of marks(out of 25)scored by 10 students was 15 .one of the student named karishma enquired the other 9 students and find the deviations from her marks are noted as -8,-6,-3,-1,0,2,3,4,6.find karishma marks.
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arithmetic mean(a.m.)= sum of observations(sn)/no. of observations(n)
n=10
am=15
=>15=sn/10
=>15*10=sn
=>150=sn
then, let karishma's marks be x
therefore,
150=x+8+x+6+x+3+x+1+x+0+x-2+x-3+x-4+x-6+x
=> 150= 10x+3
=> 147= 10x
=> 14.7= x [Ans]
*please verify the answer once
n=10
am=15
=>15=sn/10
=>15*10=sn
=>150=sn
then, let karishma's marks be x
therefore,
150=x+8+x+6+x+3+x+1+x+0+x-2+x-3+x-4+x-6+x
=> 150= 10x+3
=> 147= 10x
=> 14.7= x [Ans]
*please verify the answer once
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