Math, asked by thomalagayathri, 5 months ago

Arun bought a car for Rs 3,50,000 . Next year ,the price went upto Rs
3,70,000.What was the percentage increase in the price ?

Answers

Answered by Anonymous
5

Answer:

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Step-by-step explanation:

Increased in price of a car from Rs. 3,50,000 to Rs. 3,70,000

Amount change = Rs.3,70,000 − Rs.3,50,000 = Rs.20,000

Therefore, Increased percentage =

 \frac{amount \:  \: of \:  \: change}{original \:  \: amount}   \times 100\\   \\ =  \frac{20000}{350000}  \times 100  \\  \\  = 5 \frac{5}{7} \:  \%

Hence, the percentage of price increased is

5 \frac{5}{7}  \:  \: \%

Answered by aaxii
0

From the question, it is given that

Arun bought a car for = ₹ 350000

The price of the car in the next year, went up to = ₹ 370000

Then increase in price of car = ₹ 370000 – ₹ 350000

= ₹ 20000

The percentage of price increase = (₹ 20000/ ₹ 350000) × 100

= (2/35) × 100

= 200/35

= 40/7

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