Question

arun can do work in 18 days while veer and Abhishek together can do the same work in 6 days.if efficiency of veer is 60% more than arun,then find in how many days abhishek can completed the work alone​

Answer 1

Answer:

12.85 days

Explanation:

Let Veer and Abhishek can complete the given work in 'x' and 'y' days respectively.

⇒ Work done by Veer in one day = 1/x

⇒Work done by Abhishek in one day = 1/y

Arun can complete a work in 18 days.

⇒work done by Arun in 1 day = 1/18

According to question, efficiency of Veer is 60% more than that of Arun.

⇒ Veer can do 1.6 times the work done by Arun in same amount of time.

⇒1/x = 1.6/18

⇒ x = 11.25 days

Thus, Veer takes 11.25 days to complete the given work.

Also from the question, Veer and Abhishek can complete the work together in 6 days.

⇒ 1/x + 1/y = 1/6  

Putting 1/x = 1/11.25

⇒1/11.25 + 1/y = 1/6

⇒1/y = 1/6 - 1/11.25

⇒1/y = 0.0777

⇒y = 12.85 days

Hence, Abhishek takes 12.85 days to complete the given work.

Answer 2

Answer:

Arun 18

veer +abhi 6

lcm= 18

eff of arun 1

V+abhi 3

efficiency of veer 1.6

abhi. 1.4

abhi= 180/14

=. 12.85