arun can do work in 18 days while veer and Abhishek together can do the same work in 6 days.if efficiency of veer is 60% more than arun,then find in how many days abhishek can completed the work alone
Answers
Answer:
12.85 days
Explanation:
Let Veer and Abhishek can complete the given work in 'x' and 'y' days respectively.
⇒ Work done by Veer in one day = 1/x
⇒Work done by Abhishek in one day = 1/y
Arun can complete a work in 18 days.
⇒work done by Arun in 1 day = 1/18
According to question, efficiency of Veer is 60% more than that of Arun.
⇒ Veer can do 1.6 times the work done by Arun in same amount of time.
⇒1/x = 1.6/18
⇒ x = 11.25 days
Thus, Veer takes 11.25 days to complete the given work.
Also from the question, Veer and Abhishek can complete the work together in 6 days.
⇒ 1/x + 1/y = 1/6
Putting 1/x = 1/11.25
⇒1/11.25 + 1/y = 1/6
⇒1/y = 1/6 - 1/11.25
⇒1/y = 0.0777
⇒y = 12.85 days
Hence, Abhishek takes 12.85 days to complete the given work.
Answer:
Arun 18
veer +abhi 6
lcm= 18
eff of arun 1
V+abhi 3
efficiency of veer 1.6
abhi. 1.4
abhi= 180/14
=. 12.85