Math, asked by premapoovaje, 1 month ago

Arun covers first lap of 100 m in 13 seconds and the second lap of 100 m in 9 seconds, then the average time taken is​

Answers

Answered by rajeebsc001
0

Answer:

Arun's speed In first Lap,

s1 = d/t = 100/13 = 7.69ms-¹

Arun's speed In second Lap,

s2 = d/t = 100/9 = 11.11ms-¹

Arun's Avg speed,

S = (s1+s2) /2= (7.69+11.11)/2

= 18.8/2

= 9.4ms-¹

Step-by-step explanation:

Average speed of Arun = 9.4ms-¹

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