Question

Arun drops a clean iron nail into Copper Sulphate solution and observes
after half an hour.
a) What is the colour of the solution now?
b) What is the colour of the iron nail now?
c) Why was there a change in the colour of the iron nail?
d) What is the name of this reaction?
e) Write a balanced chemical equation for the same.

Answer 1

Answer:

a) When Iron nail (Fe) kept in Copper sulphate (CuSO4) there takes reaction between them. As Iron is more reactive than Copper it can replace Copper from CuSO4.

Fe + CuSO4 → FeSO4 + Cu

CuSO4 is in blue Colour and FeSO4 is in light green colour.

So, there will be change in the composition and colour of the solution (from blue to light green). And decomposition of Copper layer on surface of nail.

b) Iron nails become brownish in colour and the blue colour of copper sulphate solution fades.

c) This is because iron displaces copper from copper sulphate solution and forms ferrous sulphate which is colourless.

d) Displacement reaction {because iron displaces copper from copper sulphate solution.)

e) The balanced equation for this reaction is Fe(s) + CuSO4(aq) FeSO4(aq) + Cu(s).