Question

Arun exercised for 2/10 of an hour while Amit exercised for ¼ of an hour. Who exercised for a longer time and by how much ?​

Answer 1

Answer:

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{❥Solution:}$

$\sf{Arun \: exercised = \frac{2}{10} \: hours}$

$\sf{Amit \: exercised = \frac{1}{4} \: hours}$

$\sf{So,}$

$\sf{L.C.M \: of \: 10 \: and \: 4 =2 \times 2 \times 5 = 20 }$

$\sf{ \frac{2}{10} = \frac{2}{10} \times \frac{2}{2} = \frac{4}{20}} \\ \\ \sf{ \frac{1}{4} = \frac{1}{4} \times \frac{5}{5} \: = \frac{5}{20}}$

$\sf{∴ \frac{4}{20} < \frac{5}{20}} \\ \\ \sf{ \frac{2}{10} < \frac{1}{4}}$

$\sf{Hence, \: Amit \: exercised \: longer\: than \: Arun}$

Step-by-step explanation:

Hope it helps you!

Answer 2

Answer:

L.C.Mof10and4=2×2×5=20

\begin{gathered} \sf{ \frac{2}{10} = \frac{2}{10} \times \frac{2}{2} = \frac{4}{20}} \\ \\ \sf{ \frac{1}{4} = \frac{1}{4} \times \frac{5}{5} \: = \frac{5}{20}}\end{gathered}

10

2

=

10

2

×

2

2

=

20

4

4

1

=

4

1

×

5

5

=

20

5

\begin{gathered} \sf{∴ \frac{4}{20} < \frac{5}{20}} \\ \\ \sf{ \frac{2}{10} < \frac{1}{4}}\end{gathered}

∴

20

4

<

20

5

10

2

<

4

1

\sf{Hence, \: Amit \: exercised \: longer\: than \: Arun}Hence,AmitexercisedlongerthanArun