Math, asked by pandyakavita8, 11 months ago

arun got 35 out of 40 in english in first term examination and 45 out of 50 in english in the 2 nd term examination in which term did he get better percentage

Answers

Answered by abhinaysachan38
2

Answer:


Step-by-step explanation:

first term marks=35

Total marks=40

Percentage=35/40×100

=87.5%

Second term marks=45

Total marks=50

Percentage=45/50×100

=90%

He will get more percentage in 2nd term.

Hope it helps u

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Answered by Anonymous
5
Sol)
hey \: mate \: here \: is \: your \: answer \: \\ \: \: \: \: in \: first \: term \: \\ arun \: obtained \: = \frac{35}{40} \times 100 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 87.5\% \\ \: \: \: \: \: \: \: in \: 2nd \: term \\arun \: got \: = \frac{45}{50} \times 100 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 90\% \\ in \: 2nd \: he \: got \: better \: percentage \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \infty hope \: it  helps \: u \infty

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