Math, asked by archudavda, 1 year ago

Arun has 30 matchboxes of which 18 have red cover and 12 have blue cover. Ajay has 20 red and blue coloured matchboxes. if the ratio of the red matchboxes to the blue matchbox is same for both arun and ajay how many more blue matchbox s do arun have than ajay ...??​

Answers

Answered by santy2
2

Answer:

4

Step-by-step explanation:

For Arun, the ratio of Red to Blue matchboxes is \frac{18}{12}=\frac{3}{2}

i.e R:B = 3:2

we are told that the ratio of the red matchboxes to the blue matchbox is same for both arun and ajay.

Using this ratio for Ajay;

Red cover matchboxes = \frac{3}{(3+2)}*20=12

Blue cover matchboxes = \frac{2}{(3+2)}*20=8

difference of blue cover matchboxes between Ajay and Arun is;

12-8=4

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