Arun has built a cubical tank with lid and each outer edge is 2.5 cm long. the outer surface of the tank excluding the base is covered with square tiles of 25 cm long. find the number of tiles required.
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Answered by
16
TOTAL AREA TO BE TILED = 4×a²
= 4×(2.5)²
= 4×6.25
= 25 cm²
total area of 1 tile = 25×25
=625 cm²
no:of tiles = 25/625
=.04
if side of tank = 2.5 m long
area to be tiled = 2.5² × 4
= 25 m²
= 2500 cm²
area of 1 tile = 625 cm²
no:of tiles = 2500/625
= 4
it's just a try
= 4×(2.5)²
= 4×6.25
= 25 cm²
total area of 1 tile = 25×25
=625 cm²
no:of tiles = 25/625
=.04
if side of tank = 2.5 m long
area to be tiled = 2.5² × 4
= 25 m²
= 2500 cm²
area of 1 tile = 625 cm²
no:of tiles = 2500/625
= 4
it's just a try
Answered by
4
Answer: 0.05 tiles
Step-by-step explanation:
The LSA of a tank = 6a^2 - area of base
= 5a^2
= 31.25 cm
The area of 1 tile = a^2
= 625 cm
No of tiles. = 31.25/625
= 0.05
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