Math, asked by vns0689, 8 months ago

Arun has x number of toys. Mayan has y number of toys. Arjun has half the number of toys that Arun has added to one-fourth of the number of toys that Mayan has. Find the number of toys which Arjun has.

Answers

Answered by Anonymous
4

Answer:

Arjun has (2x + y) / 4 number of toys.

Step-by-step explanation:

Given that, Arun has x toys

Mayan has y toys

Arjun has half the number of toys that Arun has added to one-fourth of the number of toys that Mayan has.

Therefore,

Number of toys with Arjun = (1/2 × x) + (1/4 × y)

= x/2 + y/4

= 2x/4 + y/4

= (2x + y) / 4

Answered by gsaumya352
2

Answer:

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