Math, asked by rekhaharimadhav, 7 days ago

ARUN have 3 times two rupee coins as he has five rupee coins. If he has all a sum of rupees 77 how many coins of each denomination he have ?

Answers

Answered by antony1923
0

Answer:

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Answered by deepty4088
3

Answer:

3 \times 2x \\ 5\\ (3 \times 2x + 5) = 77 \\ 6x + 5 = 77 \\ 6x = 77 - 5 \\ 6x = 72 \\ x = 72 \div 2 \\ x = 36

Step-by-step explanation:

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