Question

.Arun lends Rs. 20,000 to two of
his friends. He gives Rs. 12,000
to the first at 8 % p.a. simple
interest. Arun wants to make
a profit of 10 % on the whole.
The simple interest rate at
which he should lend the
remaining sum of money to the
second friend is :​

Answer 1

Answer: 13%

Step-by-step explanation:  Principal amount=Rs. 12,000

Rate = 8% p.a

Time=1 year

S.I= 12000*8*1/100

   =  ₹960

Total profit=20000×10×1/100=Rs. 2000

Remaining interest (profit) = (2000−960)= Rs.1040

Remaining principal = (20000−12000)=Rs. 8000

Required Rate% =1040/8000×100=13%

Final answer - 13%

Answer 2

According to the question:

• As per given in the question,Arun lends 20000 rupees to his two friends and he gives 12000 rupees to the first at 8% rate and he wanted to make a profit of 10% on whole and we are said to find how much rate of interest on money he lent to the second.

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Given:

• whole Principal = 20000 rupees
• First Principal = 12000 rupees
• First Rate = 8%

To Find:

• Rate of interest = ?

Therefore,

Desired gain on 20000 rupees

$\: \: \sf \: = 20000 \times \frac{10}{100} = 2000 \: rupees$

Using Formula:

$\: \: \sf \: simple \: interest = \frac{prt}{100}$

where....

• P = Principle
• R = Rate
• T = Time
• S.I = Simple Interest

Now substiutue the values

Simple Interest on 12000 rupees

$\: \: \sf \: = \frac{12000 \times 8 \times 1}{100} = 960 \: rupees$

$\: \: \sf \therefore \: si \: on \: rupees \: 8000 = (2000 - 960) = 1040 \: rupees$

Now,

Using Formula:

$\: \: \sf \: rate = \frac{100 \times si}{p \times t}$

Now substiute the values

$\: \: \sf \: rate = \frac{1040 \times 100}{8000} = 13 \: percent$

Hence, Rate of interest on second friend is 13% p.a.

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