Question

⇒ Arun's garden is in the form of a parallelogram whose one side is 4.8cm and other side is 1(1/2) times of this side. He wants to fence his garden four times by wire. Find the length of the wire required !

Answer 1

Step-by-step explanation:

Area of garden sq. m

Let length of garden be .

Let breadth of garden be .

Thus, sq. m

Also, ....(Since, sides are fenced.)

Putting in upper equation:

So, when m:

m

When m

m

Thus we have possibilities.

Answer 2

Given:

Garden is in Parallelogram shape.

One side = 4.8 cm

Other side = 1½ times of Side 'One'

To Find:

Length of the Wire required to fence garden Four times

Solution:

One side = 4.8 cm

Other side = 1½ of 4.8

$\begin{gathered} \implies {\tt{ \cancel{ 4.8} \times \dfrac{3}{ \cancel{2} } }} \\ \\ \implies{\tt{ 2.4 \times 3 }} \\ \\ \implies{\tt\red{ 7.2 \ cm }} \end{gathered}$

Therefore, Other Side is 7.2 cm .

$\begin{gathered} \\ \circ \: \: \: {\boxed{\tt\pink{ Perimeter_{(Parallelogram)} = 2(length_{(One \ Side )} + breadth_{(Other \ Side )} ) }}} \\ \end{gathered}$

After substituting values in suitable Place;

$\begin{gathered} \colon\implies{\tt{ Perimeter_{(Paralellogram)} = 2(4.8 + 7.2) }} \\ \\ \\ \colon\implies{\tt{ Perimeter_{(Paralellogram)} = 2(12) }} \\ \\ \\ \colon\implies{\tt{ Perimeter_{(Paralellogram)} = 2 \times 12 }} \\ \\ \\ \colon\implies{\tt{ Perimeter_{(Paralellogram)} = 24 \ cm }} \\ \end{gathered}$

Hence,

The Perimeter of Parallelogram is 24 cm.

_____________________

$\large†$ Arun wants to Fence his garden Four times by wire,

$\colon\leadsto (4 × 24)cm$

$\colon\leadsto 96 cm$

Hence,

The Length of the Wire to fence Four times is 96 cm .