Question

Aruna now places a candle at a distance of 4.5 cm in front of the convex mirror. She uses a candle that is 2.0 cm high as the object. The focal length of the convex mirror

is 6.0 cm

Calculate the size of the image formed by the convex mirror. PLS DONT SPAM FIRST ANSWER WILL BE BRAINLIEST​

Answer 1

Height of the image is  $\frac{8}{7}$ cm

Given : Height of the object is 2 cm

Focal length of the convex mirror is 6 cm

Distance of the candle from the mirror is 4.5 cm

To Find : The height of the image of the candle

Solution : Height of the image is  $\frac{8}{7}$ cm

It is given that Aruna now places a candle at a distance of 4.5 cm in front of the convex mirror. She uses a candle that is 2.0 cm high as the object. The focal length of the convex mirror is 6.0 cm

We have to find the size of the image formed by the convex mirror

We know the mirror formula is

$\frac{1}{v} +\frac{1}{u} = \frac{1}{f}$

where v is the distance of the image from the mirror

u is the distance of the object from the mirror

and f is the  focal the focal length of the mirror

Here u = 4.5 cm

f = 6 cm cm

v = ?

putting the values in mirror formula , we get

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{6} +\frac{1}{4.5}$

$\frac{1}{v} = \frac{1}{6}+ \frac{2}{9}$

$\frac{1}{v} = \frac{7}{18}$

v = $\frac{18}{7}$

Distance of the image from the mirror is  $\frac{18}{7}$

Now we know that

Magnificent (M ) $\frac{hi}{ho} = \frac{-v}{u}$  =  (here negative sign means that inverse image will formed)

(We will ignore minus sign in calculation)

Where hi is height of the image

and ho is the height of the image

M = $\frac{18}{7}\frac{2}{9} = \frac{4}{7}$

ho = 2 cm

hi = ?

$\frac{4}{7} = \frac{hi}{2}$

hi = $\frac{8}{7}$

So height of the image is  $\frac{8}{7}$ cm

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