Math, asked by aaditya200547, 8 months ago

aruns brother is 20 years older than aruns. the product of their ages after 2 years will be 341 find present ages

Answers

Answered by amitkgindia3
2

Answer:

let,

arun's age = x

arun's brother age = x + 20

after 2 years

arun's age = x + 2

arun's brothers age = x + 22

product

(x+2) (x+22) = 341

x^2 +22x + 2x +44 = 341

x^2 + 24x = 297

put x = 9

(9)^2 + 24 × 9 = 297

81 + 216 = 297

297 = 297 (satisfied)

so,

present age of arun= 9

present age of arun' brother = 20+9 = 29

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