Math, asked by atm59, 1 year ago

arunz age is 3 times his son's age 10 years ago he was five times his son's age find their present ages​

Answers

Answered by sabrinanandini2
1

\mathbb{ANSWER}

Let Arun's son's age be x

Arun's age = 3x

10 YEARS AGO

5( x - 10) = 3x - 10

5x - 50 = 3x - 10

2 x = 40

x = 20

3x = 60

\boxed{\texttt{Son's\:age\: =20\:Father's\:age\:=60}}

Answered by Ashita1512
1

\huge\bold\red{ANSWER}

AGE OF ARUNZ'S SON IS X

AGE OF ARUNZ IS 3X

ACCORDING TO THE QUESTION TEN YEARS AGO ,

AGE OF ARUNZ = 3X - 10 = 5(X-10)

3X - 10 = 5X - 50

3X - 5X = -50 + 10

-2X = -40

2X = 40

X = 40 / 2

X = 20

AGE OF ARUNZ'S SON = 20

AGE OF ARUNZ = 3 × 20 = 60

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