Math, asked by Harshithaharshi5719, 1 year ago

Arvind Arvind is 8 years older than his sister in 3 years he will be twice as old as his sister how old they are now

Answers

Answered by Anonymous
143
☆ranshsangwan☆


Let- age of his sister be x.
So, the age of Arvind will be=x+8

After 3 years
The age of his sister=x+3
The age of Arvind=x+8+3
                              =x+11=2[x+3]
EQUATION-

2[x+3]=x+11
=2x+6=x+11
=2x-x=11-6
=x=5

So the age of his sister now is 5 years and the age of Arvind is 5+8=13years.
Answered by dishadugar2010
3

Answer:

13years

Step-by-step explanation:

Let the sister's age = x years

Arvind's age = (x + 8) years.

In three years, sister's age= ( x + 3) years

In three years, Arvind's age = (x + 8 + 3) years

According to statement,

x+8+3=2(x+3)

⟹x+11=2x+6

⟹x−2x=6−11

⟹−x=−5

⟹x=5

Sister's age = 5 years

Arvind's age= 5 + 8 = 13 years.

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