Math, asked by ratan5859, 9 months ago

Aryan is twice as old as shriya five years ago his age was three times of shares age find their present age

Answers

Answered by ElsaRoy
4

Answer:

Step-by-step explanation:

Let ayan's age=a

Let shroya's age=s

According to question

a=2s

(a-5)=3(s-5)

2s-5=3s-15

s=10

a=20

Hope it helps you!!!!!!!

Answered by BrainlySamaira
32

Question: Arjun is twice as old as Shriya.Five years ago his age was three times shriya's age Find their present ages.?

solution:

\footnotesize\texttt{Let us take shriya's age be x years. }

\footnotesize\texttt{then arjun's present age would be 2x years.}

\footnotesize\texttt{shriya's age five years ago was (x-5) years. }

\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }

\footnotesize\texttt{it is given that arjun's age five.}

\footnotesize\textsf{ year ago was three times shriya's age.}

Thus,

\small\mathtt{2x-5=3(x-5) }

\small\mathtt{2x-5=3x-15 }

\small\mathtt{15-5=3x-2x }

\small\mathtt{10= x }

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.

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