Question

Aryan is twice as old as shriya five years ago his age was three times shriya age find their present age

Answer 1

let the age of shriya be x.age of Aryan be 2x
five years ago,
shriya's age=x-5
Aryan's age=2x-5
2x-5=3(x-5)
2x-5=3x-15
15-5=3x-2x
x=10
age of shriya=10 years
age of Aryan=2×10=20years

Answer 2

solution:

$\footnotesize\texttt{Let us take shriya's age be x years. }$

$\footnotesize\texttt{then aryan's present age would be 2x years.}$

$\footnotesize\texttt{shriya's age five years ago was (x-5) years. }$

$\footnotesize\texttt{aryan's age five years ago was (2x-5) years. }$

$\footnotesize\texttt{it is given that aryan's age five.}$

$\footnotesize\textsf{ year ago was three times shriya's age.}$

Thus,

➠$\small\mathtt{2x-5=3(x-5) }$

➠$\small\mathtt{2x-5=3x-15 }$

➠$\small\mathtt{15-5=3x-2x }$

➠$\small\mathtt{10= x }$

so,shriya's present age =x =10 Years .

therefore, aryan's present age =2x=2×10=20 years.