Math, asked by samszy6424, 8 months ago

Aryan is twice as older as Samaira. five years a go his age wos three times Samariya find their present age

Answers

Answered by AlluringNightingale
41

Answer :

• Samaira's present age = 10 years

• Aryan's present age = 20 years

Solution :

Here ,

It is given that , Aryan is twice as old as Samaira .

Thus ,

Let the Samaira's present age be x years .

Then , the Aryan's present age will be 2x years .

Also ,

Samaira's age 5 years ago = x - 5

Aryan's age 5 years ago = 2x - 5

According to the question ,

Five years ago , Aryan's age was three times to that of Samaira .

Thus ,

=> 2x - 5 = 3(x - 5)

=> 2x - 5 = 3x - 15

=> 3x - 2x = 15 - 5

=> x = 10

Hence ,

• Samaira's present age = x = 10 years

Aryan's present age = 2x = 2•10 = 20 years

Answered by udaybhan2017chauhan
14

Answer:

Samaira's present age is 10 yrs.

Aryan's present age is 20 yrs.

EXPLANATION---------

GIVEN-----

Aryan is twice as older than Samaira.Then,

Let the present age of Samaira be x years.

Present age of Aryan = 2x years.

Five years ago-----

Age of Samaira = x - 5

Age of Aryan = 2x - 5

A/Q

2x - 5 = 3(x - 5)

2x - 5 = 3x - 15

2x - 3x = -15 + 5

- x = - 10

x = 10

Hence,

● Present age of Samaira = x = 10 years

● Present age of Aryan = 2x = 10×2 = 20 years.

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