Math, asked by jalpapatel9428002274, 7 months ago

Aryan’s mother present age is six times aryan’s present age. Aryan’s age five years from now will be one third

of his mother’s present age. What are their present age?​

Answers

Answered by Anonymous
21

Answer:

Present age of Aryan is 5 years and his mother is 30 years.

Step-by-step explanation:

Assume that the age of Aryan is x years and mother is y years.

Aryan’s mother present age is six times aryan’s present age.

As per given condition,

→ y = 6x ................(1)

Aryan’s age five years from now will be one third of his mother’s present age.

As per given condition,

→ (x + 5) = 1/3 × y

→ x + 5 = 6x/3

→ x + 5 = 2x

→ x = 5

Substitute value of x in (1)

→ y = 6(5)

→ y = 30

Hence, the present age of:

  • Aryan = x = 5 years
  • Mother = y = 30 years
Answered by Anonymous
26

Solution

Given :-

  • Aryan’s mother present age is six times aryan’s present age
  • Aryan’s age five years from now will be one third of his mother’s present age

Find :-

  • Present age of Aryan’s mother & Aryan's

Step - Step - Explanation

Let,

  • Present age of Aryan’s mother = x years
  • Present age of Aryan’s = y years

A/C to question,

(Aryan’s mother present age is six times aryan’s present age)

➡ x = 6y ________(1)

Again,

(Aryan’s age five years from now will be one third of his mother’s present age)

➡ (y+5) = 1/3 × x

➡ 3y + 15 = x

➡ x - 3y = 15 ________(2)

Keep value by equ(1),

➡ 6y - 3y = 15

➡3y = 15

➡y = 15/3

➡y = 5

keep value of y in equ(1)

➡ x = 6 × 5

➡x = 30

Hence

  • Present age of Aryan's Mother (x) = 30 yeard
  • Present age of Aryan (y) = 5 years

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