aryav is 3 years younger than his sister keya. if the sum of their age is 27 what are their present ages
Answers
Answered by
14
let the age of brother=x
age of sister=3+x
x+3+x=27
2x=24
x=12
brother's age=12
sister's age=15
age of sister=3+x
x+3+x=27
2x=24
x=12
brother's age=12
sister's age=15
vinay210:
yes
Answered by
4
This is your answer....
let the age of sister be=x
then...
age of arav=3 +x
sum of there age =27
present age=?
3 +x +x = 27
2x +3 =27
2x =27 - 3
2x= 24
x =24/2
x= 12
age of arav= 3+x
=3+12 =15 years
age of keya=x =12years
let the age of sister be=x
then...
age of arav=3 +x
sum of there age =27
present age=?
3 +x +x = 27
2x +3 =27
2x =27 - 3
2x= 24
x =24/2
x= 12
age of arav= 3+x
=3+12 =15 years
age of keya=x =12years
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