Question

As a 2.0 kg block travels around a 3.0 m radius circle it has an angular speed of 12
rad/s. The circle is parallel to the xy plane and is centered on the zaxis, 4.0 m from
the origin. Find
(a) the magnitude of its angular momentum around the origin,
. fthenarticle about zavicic​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Angular\:Momentum(L)=216\:kg.{m}^{2}/s}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given:}$

• Mass (m) = 2 kg

• Radius (r) = 3 m

• Speed ($\sf{\omega}$)=12 rad/s

$\large\underline\pink{\sf To\:Find:}$

• Magnitude of Angular momentum (L) = ?

________________________________

We know that ,

$\large{♡}$$\large{\boxed{\sf I=m{r}^{2}}}$

I = inerta

$\large\implies{\sf 2 \times {3}^{2}}$

$\large\implies{\sf 2 \times 9}$

$\large\implies{\sf I=18}$

$\large{\boxed{\sf I=18 kg-{m}^{2}}}$

Now ,

$\large{♡}$$\large{\boxed{\sf Angular\:Momentum(L)=I \omega}}$

On putting Value :

$\large\implies{\sf 18 \times 12}$

$\large\implies{\sf 216}$

$\huge\red{♡}$$\red{\boxed{\sf Angular\:Momentum(L)=216\:kg.{m}^{2}/s}}$