Question

As a part of campaign a huge balloon with message of "awareness of cancer" was displayed from the terrace of a tall building . It was held by strings of length 8m each which inclined at an angle of 60° at the point where it was tied as shown in the figure ------
Answer this questions ---->
(1) what is the length of AB ?
(2) if the perpendiculer distance from the centre of the circle to the chord AB is 3 m then find the radius of the circle ? Please give the answer fast .I have Pre board tomorrow.
From KV Bhandup.​

Answer 1

Step-by-step explanation:

both the string has length of 8m

so AP=BP

SO ANGLE PAB =ANGLE PBA

so all the angles will be 60 degree

hence AP=BP=AB

So length of AB will be 8m

now let OM perpendicular to AB

so AM = BM

SO AM = 4M

it is given that OM=3M

BY Pythagoras radius of circle WILL BE 5METRE

Answer 2

Answer:

8m

Step-by-step explanation:

(I) Draw a line from P which is perpendicular to AB and name it as PC

Now, Angle PBC is 60°

Putting cos60° = b/h

=> 1/2 = BC/BP

=> 1/2 = BC/8. [BP=8m]

=> BC= 4m

Now, AB=2BC

So, AB=8m

(II) In Triangle OBC,

OC=3m

BC=4m

OB= √(OC)^2+(BC)^2 [Pythagoras Theorem]

OB=√(9+16)

OB=√25

OB=5m