Physics, asked by KaranG9256, 9 months ago

As a result of change in the magnetic flux linked to the
closed loop shown in the figure, an e.m.f. V volt is induced
in the loop.
The work done (in joule) in taking a charge Q coulomb once
along the loop is
(a) QV (b) 2QV (c) QV/2 (d) zero

Answers

Answered by singhsandhu432

2

Answer:

QV/2 is right answer by according

Answered by muskan8422

11

Answer:

QV/2 is your answer

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