As a system increases in volume, it absorbs 52.5 j of energy in the form of heat from the surroundings. The piston is working against a pressure of 0.500 atm. The final volume of the system is 58.0 l. What was the initial volume of the system if the internal energy of the system decreased by 102.5 j?
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Given deltaE=q+w, where deltaE=-102.5 J and q=+52.5 J, work (w) may be expressed as -P(V2-V1). Putting it all together we have -102.5 J = +52.5 J + [-0.500 atm(58.0 L - V1)]. The change in energy for the system is -102.5 J.
=> -155 J = -29 atm*L + (0.500 atm)V1
=> convert J to atm*L => -155 J (atm*L/101.34 J) = -1.5295 atm*L
=> -1.5295 atm*L = -29 atm*L + (0.500 atm)V1
+27.4705 atm*L = (0.500 atm)V1
V1 = 54.9 L = initial volume
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