Math, asked by Hafizurkhan, 1 year ago

As aeroplane is taking off from landing field has to run 50 metres. it leaves the ground in 10 sec. what is the acceleration?

Answers

Answered by MonsieurBrainly

Distance to be travelled by the aeroplane for take off(s) = 50 m.

Time taken to take off(t)= 10 s.

Initial velocity(u) = 0 m/s [as the aeroplane is starting from rest].

Final velocity(v) = 50/10 = 5 m/s.

$acceleration \: is \: the \: rate \: of \: change \: of \: velocity \: of \: an \: object.$
$acceleration \: = \: (v - u) \div t.$

$Acceleration = (5-0)/10 = 5/10 = 1/2 = 0.5 m/ {s}^{2}.$

Therefore, the acceleration of the aeroplane is
$0.5 \: m {s}^{ - 2}$

tejasgupta: How did you calculate the final velocity??

MonsieurBrainly: initial velocity is zero as it starts from rest

MonsieurBrainly: final velocity distance / time

MonsieurBrainly: distance = displacement as if is moving in a straight line

tejasgupta: thanks..... speed = dist./time !! Forgot it!

MonsieurBrainly: :) I gave all the details as to why I used distance for velocity

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