As an experiment 2 dies are rolled at the same time twice.
Answer the following questions with the information given:
What is the probability of getting 8 or 7 in both occasions?
What is the probability of getting 9 and 10 in both occasions?
Answers
Answer:
1) fav. outcomes of getting 8 = 5
fav. outcomes of getting 7 = 6
total outcomes = 36
prob. of getting 8 or 7 = 5/36 + 6/36 = 11/36
2) fav. outcomes of getting 9 = 4
fav. outcomes of getting 10 = 3
total outcomes = 36
prob. of getting 9 and 10 = 4/36 × 3/36 = 1/108
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1)get the addition factors for both 7 and 8
7=6+1,5+2,4+3,3+4,2+5,1+6
so, the probability of getting 7 is 6
8=7+1,6+2,5+3,4+4,3+5,2+6,1+7
so, the probability of getting 8 is 7
:.therefore if we roll two dice at same time then the probability of getting 7 is 6 and getting 8 is 7
but, if it is rolled twice the the probability will get doubled
6×2,7×2
:.therefore probability of getting 7 and 8 while rolling 2 dice twice is 7=12 and 8=14
2) follow the same method hope my answer help u pls mark me as the brainliest