Question

As for 4Fe()+302(g) →2FeO365
, is – 550 J/mol/K.
The process is found to be spontaneous even
at 298K because
[AH = -1650 kJ]​

Answer 1

Explanation:

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Answer 2

Answer:

For a spontaneous reaction, total entropy must be greater than zero i.e. positive

4Fe(s)+3O2(g)⟶2Fe2 O3(s)

△Hf =−1648 KJmol−1

reaction is exothermic and surroundings absorbed 1648KJ of heat.