Question

As given in the figure a series circuit connected across a 200 volt 60 hertz line consists of a capacitor of a capacitive reactance 30 ohm and non inductive resistor of 44 ohm and a coil of inductive reactance 90 ohm and resistance 36 ohm the power dissipated in the coil is​

Answer 1

The power dissipated in the coil is V(coil) =  194 V

Explanation:

I(rms) = V(rms) / z

z = √ (R1 - R2)^2 + (xL - xc)^2

z = √ (60)^2 + (80)^2

z = 100 Ω

I(rms) = 200 / 100 = 2 A

z(coil) = √(36)^2 + (90)^2

V(coil) = R x √(36)^2 + (90)^2

V(coil) =  193.86 Volt

V(coil) =  194 V

Thus the power dissipated in the coil is V(coil) =  194 V.

Two resistors of 4 ohm and 6 ohm are connected in parallel. The combination is connected across a 6 V battery of negligible resistance. Calculate the power supplied by the battery and the power dissipated in each resistor ?

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