Question

As. If sin (7 ¢ + 9°) = cos 2 ¢, find a value of ¢​

Answer 1

Answer:

$\sin(7 \alpha + 9) = \cos(2 \alpha ) \\ \sin(7 \alpha + 9) = \sin( \frac{\pi}{2} - 2 \alpha ) \\ 7 \alpha + 9 = \frac{\pi}{2} - 2 \alpha \\ 7 \alpha + 2 \alpha + 9 = \frac{\pi}{2} \\ \alpha = \frac{\pi}{18} - 1 \\ \alpha = 10 - 1 \\ \alpha = 9$

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Answer 2

Answer:

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Step-by-step explanation:

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