Question

As New Year’s resolution Ritika planned to save from her pocket money everyday.
Starting from 5th Jan she decided to save the amount equal to the date of the month. On
30th Jan, she decided to get a gift for their maid’s daughter for Rs. 50 and a birthday present for her grand father for Rs. 100.

a. What is the amount left with Ritika by the end of the month?
b. What values are depicted by Ritika? (Any 2)

Answer 1

Amount saved by Ritika is as follows,
5rs on Jan 5,6rs on Jan 6 and so on..it forms an Arithmetic Progression{A.P}

1st term(a) = 5 rs
common difference (d)= 1 rs
last term (l) = 31 rs

A.P goes as follows,
tn = a+(n-1)d
To find the number of terms.,
n = (l-a)/d
n ={ (31- 5)/1 } + 1= 26+1 = 27
n = 27

sum of first n terms in AP,
Sn = n/2 [ 2a + (n-1)d) ]
= 27/2[ ( 2×5 )+ (27-1)1]
= 486 rs

money spent by Ritika for gifts = 50 + 100 = 150 rs

(a) money left with Ritika by the end of the month = 486 - 150 = 336 rs

(b) Ritika is a caring girl and she carefully saves and spends her pocket money.

Answer 2

Answer:

Hiii

Step-by-step explanation:

The above answer is correct.

Thanks