As observed from a fixed point on the bank of a river, the angle of elevation of a temple on the opposite bank has measure 30. If the height of the temple is 20 m, find the width of the river.
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13
We,know angle of elevation is 30 degree
and height of temple is 20 m
Let, the width of the river is x m.
On solving as shown in attachment we got x is 20√3 m .
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Answered by
15
Let PQ represent the temple where P is the top of the temple. given, PQ = 20 m
R is a fixed point on the bank of a river from a temple on the opposite bank and QR is the width of the river.
∠PRQ = 30°
In ∆PQR,
cot30° = QR/PQ
√3 = QR/20
QR = 20√3 m
hence , width of the river is 20√3 m
R is a fixed point on the bank of a river from a temple on the opposite bank and QR is the width of the river.
∠PRQ = 30°
In ∆PQR,
cot30° = QR/PQ
√3 = QR/20
QR = 20√3 m
hence , width of the river is 20√3 m
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