As observed from the top 100m high light house from thr sea level the angles of depression of two ships are 30 & 45 . If one ship is exactly behind the other on the same side of the light house , find the distance between the two ships .
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ŸØÚŘ answer is in above attachment....
Its steps are given below :
♦◽▪ Use the value of Tangent 30° and 45° in ΔACD and ΔBCD respectively to get the value of AD and BD.
♦◽▪ Subtract BD from AD to get AB.
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Answer:
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= 73 m
Step-by-step explanation:
light house height's = 100 m
in triangle ABC
tan A =AB/CB
45 degrees =100/CB
1 =100/CB
CB= 100 m
in triangle ADB
tan A = AB/DB
tan A =AB/CB+ DC
1/ square root {3} = 100/100+x
[100 +x ] / square root 3 = 100
100 + x = 100*root 3
x =100 *root 3 - 100
x = 100[root 3 -1] {root 3 = 1.73}
x = 100 [1.73 -1]
x= 100 [0.73]
x = 73 m [approx}
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