Question

as observed from the top of a 10 cm 10 cm height light house from the sea level the angles of depression of two ships are 30 and 40 degree if one ship is exactly behind the other on the same side of the Lighthouse find the distance between the two shapes

Answer 1

Hope this helps!!

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Answer 2

Let AB is the light house. So AB = 75

From triangle ABC,

tan 45 = AB/BC

=> 1 = 75/BC

=> BC = 75

Again from triangle ADC

tan30 = AB/BD

=> 1/√3 = AB/(BC + CD) 

=> 1/√3 = 75/(75 + CD)

=> 1/√3 = 75/(75 + CD)

=> 75 + CD = 75√3

=> CD = 75√3 - 75

=> CD = 75(√3 - 1)

Hope it helps you, the height of the towet i took is 75cm. If u have any doubt ask me. Don't gorget to mark this answer as the brainliest.