Question

As observed from the top of a 100 m high light house from the sea level the angles of depression of two ships are 30° and 45° if one ship is exactly behind the other on the same side of the lighthouse find the distance between the two seats

Answer 1

Answer:

Answer:

height of  lighthouse = 100m

let distance travelled by the ship when the angle of depression changes from 60 to 30

DC= Y and distance BC = X

Then[ in right ∆ABC

tan 60=AB/BC

√3 = 100/x

x√3 =100

x= 100/√3......................(i)

in right ∆ ABD

tan 30 =AB/BD

1/√3 = 100/x+y

x+y =100√3 .................(ii)

From (i) and (ii) , we get

100√3+ y =100√3

y= 100√3 - 100/√3

100×3-100/√3

200/√3

y= 200/ 1.732

200.000/1732

distance traveled by the ship

= 115.47

Tip: use √3 = 1.732

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@GauravSaxena01