Question

As observed from the top of a 100 m high lighthouse this in the sea level angle of depression of two ships is 30 and 45 if ship is exactly behind the other on the same side of the lighthouse find the distance between the two ships meritnation

Answer 1

heya....!!!!!

IN ∆ ACD

tan45° = AD / DC

=> 1 = 100/DC

=> DC = 100M

in ∆ ABD,

tan30° = AD/DB

=> 1/√3 = 100/DB

=> DB = 100√3

=> DB = 100√3M


DB = DC + CD

=> 100√3= 100 + CD

=> (100√3 - 100) = CD

=> 100(1.732 - 1) = CD
[ √3 = 1.732 ]

=> CD = 100×0.732

=> CD = 73.2M

Answer 2

Answer:

!!!REFER TO THE ATTACHMENT!!