As observed from the top of a 60m high light - house from sea-level the angles of depression of two ships are 30and 45. If one ship is exactly behind the other on the same side of the light- house, find the distance between the two ships. [use3=1.732]
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Draw a diagram like this
And now
Tan 45 = 60/x.(x is the distance b/w tower and ship with 45 angle)
60/x = 1
60 = x
Tan 30 = 60/60+y.(y is the distance between two ships)
1/√3 = 60/60+y
After solving, y = 43.92
And now
Tan 45 = 60/x.(x is the distance b/w tower and ship with 45 angle)
60/x = 1
60 = x
Tan 30 = 60/60+y.(y is the distance between two ships)
1/√3 = 60/60+y
After solving, y = 43.92
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