As observed from the top of a 75 m high lighthouse from the sea level ,the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse ,find the distance between the two ships .
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tan 30=1/√3
tan 45=1
tan 30=75/x
tan 45= 75/y
therefore 75/x=1
x=75
75/y= 1/√3
therefore y=75√3
y=75x1.732=129.9
y - x = 129.9-75= 54.9
therefore 54.9 m is the answer
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