Question

As observed from the top of a 75m high lighthouse from the sea level

the angle of depression of two ships are 30°

and 60°

. If one ship is

exactly behind the other on the same side of the light house , find

the distance between the two ships.​

Answer 1

Answer:

plsss plss plss follow me.

Step-by-step explanation:

Lines PA and BD are parallel and AB is the transversal

∴∠ABD=∠PAB [Alternate angles]

So,∠ABD=30⁰

Similarly,

Lines PA and BD are parallel and AC is the transversal

∴∠ACD=∠PAC [Alternate angles]

So,∠ABD=45⁰

Since lighthouse is perpendicular to ground

∠ADB=90⁰

In right angled triangle ACD

tan45= CD/AD

1= 75/CD

CD=75 m

Similarly,

In a right angled triangle ABD

tan30= AD/BD

1/√3 = 75/BD

BD=75 √3m

BC+CD=75√3

BC+75=75√3

BC=75( √3 −1) m

Hence the distance between two ships is 75(√3−1) m.

I hope this will help you and PLEASE FOLLOW ME.