Question

As observed from top of light , 50 m above the sea level the angle of depression of ship , sailing towards it , changes from 30° to 45° .

# Determine the distance travelled by ship...​

Answer 1

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Step-by-step explanation:

Answer 2

Answer:

$1) = \tan(30) = \frac{50}{x} \\ = \frac{1}{\sqrt{3} } = \frac{50}{x} \\ = x = 50 \sqrt{3} \\ \\ \\ 2) = \tan(45) = \frac{50}{y} \\ = 1 = \frac{50}{y } \\ = y = 50 \\ \\ \\ .x + y = 50 \sqrt{3} + 50$